Only show tuples in a list where the second item is not empty

Question

I have a list of tuples like so below:

[('/home/david/Git_Stuff/rac/', '0.9.0'), ('/home/david/Git_Stuff/racingpost/', ''), ('/home/david/Git_Stuff/trading_horseracing/', '')]
[('/home/david/Git_Stuff/rac/', '0.9.0'), ('/home/david/Git_Stuff/racingpost/', ''), ('/home/david/Git_Stuff/trading_horseracing/', '')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/International/', ''), ('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/ios/', '1.3.0')]
[('/home/david/Git_Stuff/ios/', '1.3.0')]

What I want to do is only print the tuple where the second item is not blank

So the output would appear like so:


[('/home/david/Git_Stuff/rac/', '0.9.0')]
[('/home/david/Git_Stuff/rac/', '0.9.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/apache_gaming/', '5.6.0')]
[('/home/david/Git_Stuff/ios/', '1.3.0')]
[('/home/david/Git_Stuff/ios/', '1.3.0')]

I have tried using an if statement where an item is not blank and using LEN to make sure string length is higher than 0 but this will only take affect on the first tuple in the list and if I tried this again on the second tuple it would return out of range where there is only one.

Is there a better way to do this?

Thanks

So you have a list of list? What about your code. What have you tried? — kuro, Dec 16 '19 at 16:07

score 2 · Accepted Answer · edited Dec 16 '19 at 16:08

2

Use a list comprehension :

if/else in a list comprehension?

in your case :

strippedList = [x for x in list if x[1] != '']

edited Dec 16 '19 at 16:08

chepner

497,756
71
530
681

answered Dec 16 '19 at 16:03

foudian1

111
3

score 1 · Answer 2 · answered Dec 16 '19 at 15:46

1

Restrict your lists like this

a = [('toto',''), ('babar', 'x') , ('ursule','')]
b = [_ for _ in a if _[1]] # b is now [('babar', 'x')]

answered Dec 16 '19 at 15:46

jpaul

309
1
5

Only show tuples in a list where the second item is not empty

2 Answers2