JAVA: Remainder % with printf() not working

Question

I am trying to write the equivalent of

System.out.println(a + " % " + b + " = " + r);

with the print(f)

System.out.printf("%d +'%' + %d = %d",a,b,r);

but it says the format string is malformed. I am guessing it is because of the % sign. Is there a way around this?

Did you read the documentation for printf formatting? – Nicktar Dec 18 '19 at 10:23 — Nicktar, Dec 18 '19 at 10:23
Thank you! I will reread it. – Coralzee Dec 18 '19 at 10:33 — Coralzee, Dec 18 '19 at 10:33

score 1 · Accepted Answer · answered Dec 18 '19 at 10:24

1

System.out.printf("%d %% %d = %d%n", a, b, r);

Self-escaped.

Your code constructed a string with a single %. Also add a newline, by %n which can deliver \n or \r\n.

answered Dec 18 '19 at 10:24

Joop Eggen

107,315
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Thank you! It solved it. – Coralzee Dec 18 '19 at 10:30

Manikandan · Answer 2 · 2019-12-18T10:36:24.313

1

% is used as a formate specifier, instead of directly using it you can use it as char.

public static void main(String[] args) {

       int a = 6 ;
       int b = 7;
       int r = 8;
       char chr = '%';
        System.out.printf("%d + %c + %d = %d",a,chr,b,r);
    }

edited Dec 18 '19 at 10:36

answered Dec 18 '19 at 10:31

Manikandan

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score 0 · Answer 3 · answered Dec 18 '19 at 10:31

0

It should be like that

 class Main {
  public static void main(String[] args) {
    int a =10;
    int b =5;
    int r =22;

System.out.printf("%d %d %d ",a,b,r);


  }
}

answered Dec 18 '19 at 10:31

Vasim Hayat

909
11
16

JAVA: Remainder % with printf() not working

3 Answers3