IOException parsing XML document from class path resource

Question

Ok I'm currently trying mavenise a project. However my project fails to find the xml file containing the some beans. combined2.xml

I have it defined as:

    public RepeatingGrpPoC() {
    appContext = new ClassPathXmlApplicationContext(
            new String[] { "src/main/java/resources/combined2.xml",});
    c = 0;    
}

However for a reason unknown to me I constantly get the error.

Exception in thread "main" org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [src/main/java/resources/combined2.xml]; nested exception is java.io.FileNotFoundException: class path resource [src/main/java/resources/combined2.xml] cannot be opened because it does not exist at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:341) at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:302) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:143) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:178) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:149) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:212) at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:126) at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:92) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:130) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:465) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:395) at org.springframework.context.support.ClassPathXmlApplicationContext.(ClassPathXmlApplicationContext.java:139) at org.springframework.context.support.ClassPathXmlApplicationContext.(ClassPathXmlApplicationContext.java:93) at metadataPoC.RepeatingGrpPoC.(RepeatingGrpPoC.java:34) at metadataPoC.Main.main(Main.java:22) Caused by: java.io.FileNotFoundException: class path resource [src/main/java/resources/combined2.xml] cannot be opened because it does not exist at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:141) at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:328) ... 14 more

Where else would the program be looking for this file since I've given it the relative path?

isn't it usually of this pattern `"src/main/resources/combined2.xml"` ? — Bala R, May 09 '11 at 16:52
Please see my answer at : https://stackoverflow.com/a/66230703/5916535 — Nafeez Quraishi, Feb 16 '21 at 19:13

score 48 · Accepted Answer · answered May 09 '11 at 16:54

48

It is trying to load this file from the classpath and cannot find it. Try specifying just "combined2.xml" instead of "src/main/java/resources/combined2.xml" and make sure that src/main/java/resources is on your classpath.

By the way, in Maven, the standard directory for resources is src/main/resources, so I suggest you put this file there.

answered May 09 '11 at 16:54

dogbane

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sir I am getting the same error but I am using java project instead of maven. – Akash Dec 05 '19 at 10:03

Varun · Answer 2 · 2023-03-10T08:47:53.613

8

Maven, has standard directory for resources. Which is src/main/resources, so if you keep your file here it will take it.

For example

 ClassPathXmlApplicationContext ctx = new ClassPathXmlApplicationContext("application-context.xml");

I had the same problem it worked for me

edited Mar 10 '23 at 08:47

answered May 25 '15 at 13:02

Varun

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score 1 · Answer 3 · answered Apr 03 '19 at 12:25

You have to replace your .xml in resources folder, and write:

 String[] contextPaths = new String[] {"Xxx.xml"};
    new ClassPathXmlApplicationContext(contextPaths);

If you didn't any addition configuration, all .html and .xml files Spring searches in resources folder by dafault

score 1 · Answer 4 · edited Oct 25 '20 at 20:44

1

Keep .xml files in the resources folder and use ClassPathXmlApplicationContext like this:

Example:

ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");

edited Oct 25 '20 at 20:44

seshadri_c

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answered Oct 24 '20 at 19:41

Deepak pal

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CodeToLife · Answer 5 · 2023-04-11T14:22:53.100

1

2023/4

if the classpath for resources is ok but still annoys, at a very least this works in Eclipse

ClassPathXmlApplicationContext ctx = new ClassPathXmlApplicationContext("classpath:combined2.xml");

(refer to Spring docs->Core paragraph ClassPathResource in Resources-> Built-in Resource Implementations)

edited Apr 11 '23 at 14:22

answered Apr 01 '23 at 08:17

CodeToLife

3,672
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score 0 · Answer 6 · answered Jan 18 '15 at 21:44

0

Try this

appContext = new ClassPathXmlApplicationContext(
            new String[] { "/**/combined2.xml", "/**/xxx.xml"});

answered Jan 18 '15 at 21:44

Anand Devaraj

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score 0 · Answer 7 · edited Apr 03 '19 at 12:27

You can use the relative path of the xml file. Relative path: path relative to your package where the XML file is located.

E.g. assume

package = beanfactory,  
xml file name = application-context.xml,

and xml file in under this package. then provide the path as "/beanfactory/application-context.xml"

ApplicationContext factory=new 
ClassPathXmlApplicationContext("/beanfactory/application-context.xml");

This works without errors.

score 0 · Answer 8 · edited Apr 28 '20 at 08:58

0

Move combined2.xml to your resources folder.

If you want to put any other config file like applicationContext.xml, make sure you put it in resources folder.

edited Apr 28 '20 at 08:58

Captain Jack Sparrow

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answered Apr 27 '20 at 21:36

Abhimanu Rana

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arvindkumarmohan · Answer 9 · 2022-12-15T06:47:32.287

Actually there are multiple solution for it, your choose whichever you want to implement in your project.

#1stStep
1) Move "combined2.xml" file to [src/main/resource]. 
2) Use *ApplicationContext context = new ApplicationContext(parent 
   class,args);*

*The [parent class] value is actually the main java class file or the current class where you are facing this issue.

#2ndStep
If you still wanna use your method, then consider following the solution 
below:-
1) Move "combined2.xml" file to [src/main/java]
2) Use *ClassPathXmlApplicationContext context = new 
   ClassPathXmlApplicationContext("combined2.xml");*

Elaboration of #2ndStep:- You put the xml file under wrong folder [src/main/java/resources], your "combined.xml" file should be under [src/main/java]. You don't have to give full directory of the path for an example: "src/main/java/resources/combined2.xml", just put the name of the [.xml] file you have created. Based on your project, you created "combined2.xml", just pass the name of the file which is "combined2.xml". The exact solution was given below based on your project structure.

Exact Solution:-

public RepeatingGrpPoC() {
ClassPathXmlApplicationContext appContext = new 
ClassPathXmlApplicationContext("combined2.xml");
}

score -1 · Answer 10 · edited Mar 22 '21 at 01:55

-1

Put the Config file under Resource folder if you are using Maven. Like below.

enter image description here

edited Mar 22 '21 at 01:55

Jin Lee

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answered Mar 21 '21 at 18:43

Meghraj Sharma

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score -3 · Answer 11 · edited Apr 15 '22 at 12:12

-3

I got it.. correct answer

ApplicationContext appContext = new ClassPathXmlApplicationContext(
            new String[] { "/**/applicationContext.xml", "/**/xxx.xml"});

edited Apr 15 '22 at 12:12

stackprotector

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answered Apr 15 '22 at 07:34

Dr Subhash Mohandas

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Dr Subhash Mohandas , the purpose of this post is to say thanks for the several existing answers which basically propose the same solution, isn't it? If you intend to contribute additional insight please make that more obvious by [edit]ing to explain the relevant difference. – Yunnosch Aug 30 '22 at 17:27

IOException parsing XML document from class path resource

11 Answers11