How to remove entire sentence if it contains string? PHP

Question

I'm trying to clean up a large text using PHP by removing certain phrases which relate to other texts which I do not have. These phrases are typically between two html tags like <i>this</i> but I would like to remove only those which containing a keyword, which is "See also".

Is there a way to do this with preg_replace ?

Given the following input:

<h1>this is a header</h1>
<i>See also staying safe in Taiwan</i>
<p>Some long text here</p>
<i>Some more text over here</i>
<p>Some more text <i>here</i></p>

How can I remove the entire phrase containing the string "See also". Expected output:

<h1>this is a header</h1>
<p>Some long text here</p>
<i>Some more text over here</i>
<p>Some more text <i>here</i></p>

The thing to look out for is "See also".

Thank you!

You can use DOMDocument and split it into the tags and then remove any that contains the text you are after. — Nigel Ren, Dec 19 '19 at 19:23
@FelippeDuarte DON'T USE REGEX FOR THAT! https://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags — delboy1978uk, Dec 23 '19 at 11:06

score 0 · Accepted Answer · answered Jan 07 '20 at 18:05

0

This is how I resolved it:

$text = preg_replace("/<i>(See also)([^<]*)<\/i>/i",'', $text);

answered Jan 07 '20 at 18:05

James

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How to remove entire sentence if it contains string? PHP

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