Can I return an operation as output for a lambda function with if...else condition?

Question

I'm trying to increase a_s by 1 for every element of list a that is bigger than the corresponding element of list b using lambda.

>>> a = [4, 5, 8]
>>> b = [1, 3, 9]
>>> a_s = 0
>>> a_sum = map(lambda x,y: (a_s + 1) if x > y else (a_s + 0), a, b)
>>> print (a_sum)
<map object at 0x01230890>

The output I'm expecting is 2 since the 0th and 1st elements of list a are greater than that of list b

Note that the `a_s` is very superfluous here. You're not modifying it, it's only ever returning `0 + 1` or `0 + 0`… — deceze, Dec 20 '19 at 07:34
Exactly, im looking to print the sum of that map after its `list()` ified. — Samyuktha0511, Dec 20 '19 at 08:00
`a_s = sum(1 for x, y in zip(a, b) if x > y)` is probably the most sensible solution. — deceze, Dec 20 '19 at 08:15

Vaibhav Jadhav · Accepted Answer · 2019-12-20T08:09:16.233

1

Solution is:

print (sum(a_sum))

OR

res = list(a_sum)
print (sum(res))

edited Dec 20 '19 at 08:09

answered Dec 20 '19 at 07:31

Vaibhav Jadhav

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Just tried your suggestion. The output Im looking for is the sum of that output list. Is it possible to print the sum without manually adding the list elements? – Samyuktha0511 Dec 20 '19 at 08:02
@Samyuktha0511 Check the solution and let me know if you wanted the same. I have updated "print (sum(a_sum))" in the solution – Vaibhav Jadhav Dec 20 '19 at 08:14
Thank you bro!! Its working – Samyuktha0511 Dec 20 '19 at 09:45

Can I return an operation as output for a lambda function with if...else condition?

1 Answers1