How do I use a variable in a regular expression in mongoose?

Question

I've found a similar question and the answer in it didn't turn out to be working for me.
I want to do something like:

ItemModel.find({name: \^VARIABLEHERE\i});

doing a case insensitive search that finds anything that matches the variable.
Also I tried to do something on my own by using:

new RegExp(`/^${variablehere}/`, 'i')

And

new RegExp(`/^${variablehere}/i`)

Yeah I'm new to regular expressions.
All help is appreciated. :)

`$regex` [MongoDB manual](https://docs.mongodb.com/manual/reference/operator/query/regex/#examples) — sudipn, Dec 21 '19 at 18:28
@Drunk : What has not worked ? Can you give us few sample docs & required o/p & also what you're seeing now.. — whoami - fakeFaceTrueSoul, Dec 21 '19 at 19:26
@Wiktor Stribizew, this question is about mongoose, not mongodb in particular. Syntax is not exactly same. — Drunk Illuminati, Dec 22 '19 at 04:51

score 0 · Accepted Answer · edited Dec 21 '19 at 19:46

0

You can use $regex

ItemModel.find({
    name: {
        $regex: '.*' + name + '.*', //or you can use `.*${name}.*`
        $options: 'i'
    }   
});

There is a complete manual for variety of regular expression at mongodb $regex manual

edited Dec 21 '19 at 19:46

Drunk Illuminati

answered Dec 21 '19 at 19:32

1 Answers1