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I have a URL but i need only the value of http_token i.e., somedata in that URL so that i can send the token value as argument in my code. How do i get it?

URL:

https://website.com/?HTTP_TARGETPORTAL=7&HTTP_TOKEN=somedata&HSID_DOMAIN_URL=...

Hossein Zare
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Chaitanya Sbs
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    One solution is to use regular expressions for this. What have you tried? – vs97 Dec 21 '19 at 22:02
  • I didnt try anything can you share the code ? – Chaitanya Sbs Dec 21 '19 at 22:05
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    No, sorry, I will not share the code. StackOverflow is for helping with specific coding issues, not a code sharing site. Please try something first, and we can help if you struggle further. – vs97 Dec 21 '19 at 22:07
  • A regular expression allows you to define a pattern and try to match it. This is for example how you can verify if a given string is a valid email format (text.text@text.com). Check this website for more details: https://www.regular-expressions.info/ – Ama Dec 21 '19 at 22:21
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    Does this answer your question? [Getting URL parameter in java and extract a specific text from that URL](https://stackoverflow.com/questions/11733500/getting-url-parameter-in-java-and-extract-a-specific-text-from-that-url) – AElMehdi Dec 21 '19 at 22:27

2 Answers2

0

You can pass your string to URL and get the query parameters.

Here is a working solution motivated from answer: Parse a URI String into Name-Value Collection

public static void main(String[] args) {

    String givenUrl = "https://healthsafeid-stage1.optum.com/protected/accountreset/password?HTTP_TARGETPORTAL=LAWW&HTTP_TARGETURL=https%3A%2F%2Fsr-smsc-stg.liveandworkwell.com%2Fservices%2Fsecure%2Fgn&HTTP_ERRORURL=https%3A%2F%2Fsr-smsc-stg.liveandworkwell.com%2Fcontent%2Fen%2Fpublic%2Ferror.html&HTTP_ACCESSTYPE=TIER1&HTTP_BRANDURL=&HTTP_LANGUAGE=en&HTTP_ACCESSCODE=12345678&HTTP_GRADIENTCOLOR1=&HTTP_GRADIENTCOLOR2=&HTTP_TOKEN=GthzXwVHL2xyAdMsHukFPGrSrP6GJHItc%2BEucuznsQk0%2FEhFrjTfr6r0fL16SKOQvus7y5dHmZ1LP3jUJtvY2w%3D%3D&HSID_DOMAIN_URL=https%3A%2F%2Fhealthsafeid-stage1.optum.com";

    try {
        URL url = new URL(givenUrl);
        Map<String, String> query_pairs = new HashMap<>();
        String query = url.getQuery();
        String[] pairs = query.split("&");
        for (String pair : pairs) {
            int idx = pair.indexOf("=");
            query_pairs.put(URLDecoder.decode(pair.substring(0, idx), "UTF-8").toUpperCase(), URLDecoder.decode(pair.substring(idx + 1), "UTF-8"));
        }

        String httpToken = query_pairs.get("HTTP_TOKEN");
        System.out.println("Http token: " + httpToken);
    } catch (MalformedURLException | UnsupportedEncodingException e) {
        // log and handle the exception
    }
}

Output:

Http token: GthzXwVHL2xyAdMsHukFPGrSrP6GJHItc%2BEucuznsQk0%2FEhFrjTfr6r0fL16SKOQvus7y5dHmZ1LP3jUJtvY2w%3D%3D

Advantage with this approach:

  1. Not dependent on the order of the query parameters
  2. Also parses other parameters. They can be stored as well if needed for future purpose.
Sunil Dabburi
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  • Tried : String params1 = "URLllllllllllllllllll"; try { Pattern p = Pattern.compile("HTTP_TOKEN=([^&]+)"); Matcher m = p.matcher(params1); while (m.find()) { System.out.println(m.group()); } } catch (PatternSyntaxException ex) { // error handling } } – Chaitanya Sbs Dec 21 '19 at 23:03
0

I've not worked with Java regular expressions but the whole thing should be this.

I'm not sure this will work or not. There are many ways to achieve the expected result but here is the regex way.

String line = ""; // URL HERE
String pattern = "HTTP_TOKEN=(.+)[&]*";

// Create a Pattern object
Pattern r = Pattern.compile(pattern);

// Now create matcher object.
Matcher m = r.matcher(line);
if (m.find()) {
    System.out.println("HTTP TOKEN: " + m.group(1) );
}else {
    System.out.println("NOT FOUND");
}

Regex Preview: https://regex101.com/r/mA8bPg/2

Hossein Zare
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