consider two lists a=[1,2,3], b=[1,4,5].The Code should print the similar values c=[1] and the Code should print d=[2,3,4,5] which shows different values
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@vicrobot : can u help me with ur question – Raja Dec 23 '19 at 11:57
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where do u stuck when you try solving that problem? – Vicrobot Dec 23 '19 at 11:59
2 Answers
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A simple and alternative solution using list comprehension and logical operators is given below:
a = [1,2,3]
b = [1,4,5]
print([x for x in a if x in b])
print([x for x in set(a+b) if (x in a) ^ (x in b)])
A solution with set operation has already been given by other person, so I am not repeating it here.
abhiarora
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You can use sets for this
a = [1,2,3]
b = [1,4,5]
c = list(set(a).intersection(b))
d = list(set(a).difference(b)) + list(set(b).difference(a))
intersection finds the common elements and difference finds what is different. You have to do this both ways because the difference operator is basically showing only the elements in the first set that aren't in the second.
CumminUp07
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