How to Remove special characters at the end and at the begging of the string

Question

I have a string:

String str = "    line0\n" +
                "line1\n" +
                "line2    line0\n" +
                "line3\n" +
                "line4   \n"

How can I get the following script:

String formatedStr = "line0\n" +
                    "line1\n" +
                    "line2    line0\n" +
                    "line3\n" +
                    "line4"

Does this answer your question? [Correct way to trim a string in Java](https://stackoverflow.com/questions/20291307/correct-way-to-trim-a-string-in-java) — SternK, Dec 26 '19 at 10:27
`formatedStr.trim().replace("(^\\\\n*|(\\\\n)$)", "")` use regex to replace leading and trailing character with empty string — Navin Gelot, Dec 26 '19 at 11:00

score -1 · Accepted Answer · answered Dec 26 '19 at 10:32

-1

You can do it as follows

String formattedStr = str.trim();

Refer java-string-trim-method-example for more details.

answered Dec 26 '19 at 10:32

Guru Vishnu Vardhan Reddy

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How to Remove special characters at the end and at the begging of the string

1 Answers1