I have a list of words. I want to create a dictionary in which I have a count of every word in the format <"word" : count(INT)>.
for example:
words = [
'look', 'into', 'my', 'eyes', 'look', 'into', 'my', 'eyes', 'the', 'eyes',
'the', 'eyes', 'the', 'eyes', 'not', 'around', 'the', 'eyes', "don't",
'look', 'around', 'the', 'eyes', 'look', 'into', 'my', 'eyes', "you're",
'under'
]
and the dictionary should be like:
count_dict = {
"look" : 4,
"into" : 3,
"my" : 3,
"eyes" : 8,
"the" : 5,
"not" : 1,
"around" : 2,
"don't" : 1,
"you're" : 1,
"under" : 1
}
The code that I tried is:
count_d = dict({})
for word in words:
if len(count_d) == 0:
count_d.update({word: 1}) # null dict checking
else:
for key in list(count_d.keys()):
if key == word: # if key already present
initial_value = count_d[key]
new_value = count_d[key] + 1
count_d.update({key : new_value})
else: # if key is not present
count_d.update({word : 1})
From this code, every key has a 1 value in the dict. Help me with this, I know this is very basic but I am a newbie in this. Thanks in advance.