How can I print two counter side by side in python?

Question

I have a function like this.I need to print two dictionaries side by side in python.

def kelime_sayma(metin):
    kelimeler = metin.split()
    kelime_sayi = Counter(kelimeler)

    for i,value in kelime_sayi.most_common():
        print('{}    {}'.format(i, value))
    for j,value in sorted(kelime_sayi.items()):
        print('{}    {}'.format(j, value))

Are you using `collections.Counter` or is it something else? Can you show us the content of the `metin` arg? — enbermudas, Dec 27 '19 at 13:53
What is your expected output? What do you mean side by side? — CumminUp07, Dec 27 '19 at 13:58
metin is a text that getting from user. I need a program that prints the number of times words in a text are used. @DeveshKumarSingh — mcora, Dec 27 '19 at 14:08
If I use this function , dictionaries are printed one by one but I need to print side by side. @CumminUp07 — mcora, Dec 27 '19 at 14:10

score 1 · Accepted Answer · answered Dec 27 '19 at 14:08

You can try :

>>> a
['c', 'a', 'b', 'b', 'c', 'b', 'b', 'b', 'a', 'a', 'b', 'a', 'b', 'c', 'c', 'a', 'c', 'a', 'a', 'b', 'a', 'a', 'c', 'a', 'b', 'c', 'c', 'c', 'b', 'a']
>>> b=Counter(a)
>>> b
Counter({'a': 11, 'b': 10, 'c': 9})
>>> for i,j in zip(b.most_common(), b.items()):
...     print('{} {} {} {}'.format(i[0], i[1], j[0], j[1]))

Output:

a 11 c 9
b 10 a 11
c 9 b 10

score 1 · Answer 2 · answered Dec 27 '19 at 14:08

1

Question: print two dictionaries side by side

zip(*iterables)

    for i, v1, v2 in enumerate(zip(kelime_sayi.most_common(), sorted(kelime_sayi.items()), 1):
        print('{}    {} {}'.format(i, v1, v2))

answered Dec 27 '19 at 14:08

stovfl

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How can I print two counter side by side in python?

2 Answers2