reversing a string starting and end bounds

Question

I understand that when slicing strings, the first index number refers to the start (inclusive), second number refers to end (exclusive) and the third refers to step size. So, wouldn't the first example throw an index error since length 6 is outside of the string? In the second example I would've expected "nohty" and "ohty" for the third example but this is clearly not the case.

temp = 'Python'
stringLen = len(temp)
slicedStr = temp[stringLen::-1]
print(slicedStr)
>>> nohtyP

stringLen = len(temp) - 1
slicedStr = temp[stringLen::-1]
print(slicedStr)
>>> nohtyP

stringLen = len(temp) - 2
slicedStr = temp[stringLen::-1]
print(slicedStr)
>>> ohtyP

I would suggest look here then the duplicate link: https://stackoverflow.com/questions/9490058/why-does-substring-slicing-with-index-out-of-range-work — Boendal, Dec 31 '19 at 05:40

score 0 · Answer 1 · edited Mar 07 '20 at 20:36

0

Try this

print(temp[-1::-1])

now the first index will point to the last character.

edited Mar 07 '20 at 20:36

Ch3steR

20,090
4
28
58

answered Dec 31 '19 at 05:24

Shashikumar KL

1,007
1
10
25

reversing a string starting and end bounds

1 Answers1