splitting out the list in python

Question

I have the list as below :

item = ['3138591780' ,'3145056746' ,'3228083330' ,'3230089832' ,'3238650148' ,'3241690762' ,
         '3257712043' ,'3754126989' ,'3799112085' ,'3801697389' ,'3801701129' ,'3801708081']

I want to pick the 3 items from this iterative manner so in first iteration it will return sublist as ['3138591780' ,'3145056746' ,'3228083330'] . 2nd iteration it will return ['3230089832' ,'3238650148' ,'3241690762'] How can I achieve this ?

thanks

Marco · Accepted Answer · 2019-12-31T18:49:34.210

1

This should be quite simple:

item = ['3138591780' ,'3145056746' ,'3228083330' ,'3230089832' ,'3238650148' ,'3241690762' ,
         '3257712043' ,'3754126989' ,'3799112085' ,'3801697389' ,'3801701129' ,'3801708081']

while len(item) > 0:
    if len(item) >= 3:
        slice_size = 3
    else:
        slice_size = len(item)
    slice = item[:slice_size]
    for elem in slice:
        item.remove(elem)
    print (slice)

edited Dec 31 '19 at 18:49

answered Dec 31 '19 at 17:42

Marco

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Thank you, slice did the trick . But only caveats I am seeing is that if I have 11 items then last 2 is not derived . Anyway to handle this as well ? – pauldx Dec 31 '19 at 18:19
This should work! – Marco Dec 31 '19 at 18:38
do you have idea rather printing the slice how can I get each slice in separate list that means slice[1] will be showing 3 items and slice[2] will be showing next 3 ? and that was the actual intent to split into separate list – pauldx Dec 31 '19 at 19:58

splitting out the list in python

1 Answers1