comparing every element in a list python

Question

i want to compare every element of a list and see if there is an element which occurs more than once my code doesn't function, i want to return False if there is one element that occurs more than once, True if all elements are different. i have tried this so far:

def diffElements(liste):
   i = 0
   j = 1
   while i < len(liste):
       if liste[i] == liste[j]:
           return False
       j += 1
       if j == len(liste) - 1:
        print("Jj: " + str(j))
           i += 1
           j = i + 1

Looks like you've got an indentation error on the line you're using to print - that could be causing trouble. — Nick Reed, Jan 02 '20 at 16:30
Create a set from the list and return if their sizes are different. — quamrana, Jan 02 '20 at 16:30
You have not explained *what* the problem is, which makes it hard to say *how* to fix it. — Scott Hunter, Jan 02 '20 at 16:31
[Here](https://stackoverflow.com/questions/16603282/how-to-compare-each-item-in-a-list-with-the-rest-only-once) is a similar post — Nibrass H, Jan 02 '20 at 16:32
Note that your function *never*, under any circumstances, returns `True`. — Scott Hunter, Jan 02 '20 at 16:32

score 4 · Answer 1 · answered Jan 02 '20 at 16:31

4

Use a set to detect duplicates:

def diffElements(liste):
    return len(set(liste)) != len(liste)

answered Jan 02 '20 at 16:31

quamrana

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comparing every element in a list python

1 Answers1