How To Remove an Element from a List Using Another List's Placeholder in Python

Question

I need to remove a certain element from a list of dictionaries. Unfortunately, the only reference to the object needing removal is a place in another list:

enemy_list[num]

I need to take out enemy_list[num] from everyone.

ii = 0
for i in enemy_list:
  print(ii, ':', enemy_list[ii])
  ii += 1
num = input("Which of your opponents would you like to eliminate? ")
num = int(num)
del everyone[enemy_list[num]]

I cannot remove it from only enemy_list because it is reset multiple times as everyone in list everyone takes a turn. I tried this question, but it only worked from removing entire lists from eachother. Is there a way I could change it to work for this case? Thanks for your time!

You only want to remove a certain element. Why not just use `list.remove`? — sshashank124, Jan 03 '20 at 14:45
It doesn't work, because I don't know what said element is, aside from its place inside list1. — Frasher Gray, Jan 03 '20 at 14:47
What are they lists of? objects? do they hold the same reference? It would really help to create a [mcve]. — Sayse, Jan 03 '20 at 14:49
Based on what you have described, `remove` should work. Proof: https://repl.it/repls/SizzlingWorthwhileShell — sshashank124, Jan 03 '20 at 14:55

score 0 · Accepted Answer · answered Jan 03 '20 at 14:51

0

everyone.remove(enemy_list[num])

answered Jan 03 '20 at 14:51

Sadru

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OP has already stated that it doesn't work – sshashank124 Jan 03 '20 at 14:52
This actually does work, I was calling the wrong function inside my code. XD – Frasher Gray Jan 03 '20 at 14:55

How To Remove an Element from a List Using Another List's Placeholder in Python

1 Answers1