How to assign a char* pointer to a char variable in c

Question

I have a struct Track with variable like this char artist[81];

I have a function to create a new track Track *newTrack(char *artist, char *title, int time);

But doing this is not possible..

track->artist = artist;

How can I transform a char array into a char?

Does this answer your question? [Proper way to copy C-strings](https://stackoverflow.com/questions/9593798/proper-way-to-copy-c-strings) — Aykhan Hagverdili, Jan 06 '20 at 12:51
Your destination field is not _a char variable_, but an array of chars: a string. — Roberto Caboni, Jan 06 '20 at 15:26

score 1 · Answer 1 · answered Jan 06 '20 at 12:33

1

you can use strcpy ,

    strcpy(track->artist, artist);

include header

      #include<string.h>

answered Jan 06 '20 at 12:33

fariz

51
7

score 1 · Answer 2 · answered Jan 06 '20 at 15:33

In this case you can use strcpy in this way:

strcpy(track->artist, artist);

but pay attention:

To avoid overflows, the size of the array pointed by destination shall be long enough to contain the same C string as source (including the terminating null character), and should not overlap in memory with source.

for more details i leave you a useful link : strcpy

How to assign a char* pointer to a char variable in c

2 Answers2