Regx to delete a given pattern in string

Question

In the xml we have some tags like

<string1 : string2>

and many more like this.

i need to write a regular expression to delete all the string end with ":" and i.e. here string1 and ":" also. and it should be always inside < >

e.g. Input = <string1 : string2>

output = <string2>

do you need to catch closing tags with the same format? – Jeff May 11 '11 at 13:50 — Jeff, May 11 '11 at 13:50

anubhava · Answer 1 · 2011-05-11T15:00:01.497

1

This is how you do it in php:

<?php
 $str = "<string1 : string2>";
 $s = preg_replace('~(</?)[^>:]*:\s*~', "$1", $str);
 var_dump($s);
?>

EDIT In Java

String str = "<ns2:senderId xmlns=\"netapp.com/fsoCanonical\">NetApp</ns2:senderId>";
System.out.println(str.replaceAll("(</?)[^>:]*:\\s*", "$1"));

Output

<senderId xmlns="netapp.com/fsoCanonical">NetApp</senderId>

edited May 11 '11 at 15:00

answered May 11 '11 at 13:50

anubhava

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@satyam: based on comments I have provided you one example in Java above. Hope that meets your requirement. – anubhava May 11 '11 at 15:01

sverre · Answer 2 · 2011-05-11T14:00:22.990

0

<.*?:\s*(.*?)> should capture only the part you are interested in. How to do regex replacement can vary from programming language to programming language.

In java you could do

string.replaceAll("<.*?:\s*(.*?)>", "<$1>");

edited May 11 '11 at 14:00

answered May 11 '11 at 13:49

sverre

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so could to tell me how to do it in java – satyam May 11 '11 at 13:54

score 0 · Answer 3 · answered May 11 '11 at 13:51

0

<[^>:]*:\s*([^>]*)>

Search and replace with <$1>.

answered May 11 '11 at 13:51

Jeff

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Hi jeff thanks a lot its working ,but one more exception.. lets say we have input xml like this NetApp Unisys 4CF4DC05126A0077E10080000A66C871 and we need the output as below – satyam May 11 '11 at 14:17
NetApp Unisys 4CF4DC05126A0077E10080000A66C871 – satyam May 11 '11 at 14:22

score 0 · Answer 4 · edited May 23 '17 at 10:34

0

With an xslt parser you can use

<xsl:template match="*">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>
<xsl:template match="@*|text()|comment()|processing-instruction()">
    <xsl:copy-of select="."/>
</xsl:template>

This link is relevant for your question.

edited May 23 '17 at 10:34

Community

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answered May 11 '11 at 13:51

Captain Giraffe

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score 0 · Answer 5 · answered May 11 '11 at 13:58

(?<=<).*?:\s*(?=.*?>)

The look behind ensures the < is on the left, then matches your string including the : and optional whitespaces. The following look ahead ensures that there is the rest of the tag.

Capture this and replace with an empty string.

You can it see online here http://regexr.com

regular-expressions.info/java.html explains how to apply regexes in java.

Regx to delete a given pattern in string

5 Answers5

EDIT In Java