Java why is this array equals printing false?

Question

Why does this code print false? I've tried the code below as well as using the somea.equals(somea2); method and still i get false. how are these two arrays different?

int[] somea = {2};
int[] somea2 = {2};
System.out.println(somea==somea2);

false

what could possibly be going wrong?

because both are objects, which have the same value but are't the same — Maxdola, Jan 08 '20 at 23:13
Because they are not the same array. They're two different arrays currently containing the same value. — khelwood, Jan 08 '20 at 23:17

score 2 · Accepted Answer · answered Jan 08 '20 at 23:25

You are comparing the 2 address. Maybe you can use the java.util.Arrays.equals(int[] a, int[] a2) method that returns "true" if the two specified arrays of ints are equal to one another. Two arrays are equal if they contain the same elements in the same order.Two array references are considered equal if both are null.

Example :

int[] somea = {2};
int[] somea2 = {2};
System.out.println(Arrays.equals(somea , somea2 ));

You can read more from here: https://www.tutorialspoint.com/java/util/arrays_equals_int.htm

score 0 · Answer 2 · answered Jan 08 '20 at 23:18

0

This is because soma and soma2 is not primitive type. They are reference type. Reference type variables have references for memory.

answered Jan 08 '20 at 23:18

Rurou2

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Timetrax · Answer 3 · 2021-10-14T20:24:03.400

0

the arrays live in different cities of the memory and you are asking the machine if the cities where they live is are the same. however, both cities have a street named grand avenue. you want to be asking the machine if both cities have a street named grand avenue

edited Oct 14 '21 at 20:24

answered Jan 08 '20 at 23:26

Timetrax

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score -1 · Answer 4 · answered Jan 08 '20 at 23:16

-1

Cause you are comparing the address of these two arrays,

answered Jan 08 '20 at 23:16

Richard

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Java why is this array equals printing false?

4 Answers4