How to handle errors when extracting zip files using extract-zip in NODE JS?

Asked Jan 10 '20 at 10:30

Active Jan 10 '20 at 10:30

Viewed 269 times

I am currently using extract-zip to unzip the zip files uploaded to the server in my project. I am trying to catch the error that throws when extracting zip files with invalid file names. But it crashes the server when a zip file is uploaded with invalid file paths like paths containing back slashes.

My code is as follows;

extract(filePath, { dir: extractFiledir }, function (err) {
                if (err) {
                  logger.error("[menu_service] :: importCourse() : error ::" + err);
                  return res.status(500).json({ status: { code: 500, name: i18n.__('Error'), message: i18n.__('Error') }, payload: null });
                } else {
                 //if successfully extracted
                  }
});

It doesn't catch the error instead it crashes the server without returning the response.

asked Jan 10 '20 at 10:30

WLVF

What's the error in the console(or log file) when the server crashes? – Ajay Dabas Jan 10 '20 at 10:32
It says invalid characters in fileName. – WLVF Jan 10 '20 at 11:05
Refer to the accepted answer in [this](https://stackoverflow.com/questions/35348836/illegal-characters-in-path-when-extracting-zip-file-with-c-sharp) post. – Ajay Dabas Jan 10 '20 at 13:43
Okay thanks a lot. – WLVF Jan 11 '20 at 00:35

How to handle errors when extracting zip files using extract-zip in NODE JS?

0 Answers0