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so i'm using opencv in python to look at a specific part of screen using this code:

import numpy as np  
from PIL import ImageGrab  
import cv2  

while(True):  
  printscreen_pil =  ImageGrab.grab(bbox=(852,530,911,575))  
  printscreen =   np.array(printscreen_pil.getdata(),dtype='uint8')\  
  .reshape((printscreen_pil.size[1],printscreen_pil.size[0],3))   
  cv2.imshow('window',cv2.cvtColor(printscreen, cv2.COLOR_BGR2GRAY))  
  if cv2.waitKey(25) & 0xFF == ord('q'):  
    cv2.destroyAllWindows()  
    break

I want to give an output whenever this part of the screen matches an image. I'm stuck and reading up on 100 different tutorials but I'm stuck at the moment.

wolf roels
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  • Is [this](https://stackoverflow.com/questions/27343997/using-pil-python-image-library-to-detect-image-on-screen) answers your question ? – nakE Jan 14 '20 at 19:49
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    Please indent your code correctly - it makes a difference in Python. If you can't be bothered to write it properly or check it, you won't incentivise folk to help you. – Mark Setchell Jan 14 '20 at 20:28
  • Please note PIL grabs in RGB, not BGR. – Mark Setchell Jan 14 '20 at 20:29
  • it's pointless using `getdata()` to convert the image to a list, then go to Numpy, then `reshape()` it back to an array. Just use `npim = np.array(printscreen_pil)` – Mark Setchell Jan 14 '20 at 20:32

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