In the query below, I used the LISTAGG
function to aggregate certificate names I.e. JPM_DESCR90
. However, now I'm trying to find a way to remove all the duplications in the row, and reducing the space between the values in the All_ CERTIFICATIONS
column. For the duplications, I've used the distinct
function i.e. LISTAGG( DISTINCT C.JPM_DESCR90,',')
as well as a number of other functions, but none of them seem to work.
SELECT A.EMPLID, A.JOBCODE, A.JOBCODE_DESCR, A.EMPL_STATUS, A.LOCATION, A.LOCATION_DESCR, A.NAME, E.EMAILID, B.EMPLID, E.OPRID, MAX( TO_CHAR(C.JPM_DATE_3,'YYYY-MM-DD')) AS Latest_Certification_Date ,LISTAGG( C.JPM_DESCR90,',') WITHIN GROUP ( ORDER BY C.JPM_DESCR90) AS All_Certifications
FROM PS_NPS_VIEW_ALL A, (PS_PERSON_NAME B LEFT OUTER JOIN PS_NPS_LIC_VW_RPT C ON B.EMPLID = C.EMPLID ), PSOPRDEFN E
WHERE ( A.EFFDT =
(SELECT MAX(A_ED.EFFDT) FROM PS_NPS_VIEW_ALL A_ED
WHERE A.EMPLID = A_ED.EMPLID
AND A.EMPL_RCD = A_ED.EMPL_RCD
AND A_ED.EFFDT <= SYSDATE)
AND A.EFFSEQ =
(SELECT MAX(A_ES.EFFSEQ) FROM PS_NPS_VIEW_ALL A_ES
WHERE A.EMPLID = A_ES.EMPLID
AND A.EMPL_RCD = A_ES.EMPL_RCD
AND A.EFFDT = A_ES.EFFDT)
AND A.EMPLID = B.EMPLID
AND A.EMPLID = E.EMPLID
AND A.PER_ORG = 'EMP'
AND A.EMPL_STATUS='A'
AND A.PAYGROUP NOT IN ('SUM','CWR'))
GROUP BY A.EMPLID, A.JOBCODE,A.JOBCODE_DESCR, A.EMPL_STATUS, A.LOCATION, A.LOCATION_DESCR, A.NAME, E.EMAILID, B.EMPLID, E.OPRID;
The distinct function wouldn't work because I was using Oracle 12 c.
Another thing I tried was to use a nested select statement.
SELECT A.EMPLID, A.JOBCODE,A.JOBCODE_DESCR, A.EMPL_STATUS, A.LOCATION, A.LOCATION_DESCR, A.NAME, E.EMAILID, B.EMPLID, E.OPRID,
LISTAGG(C.JPM_DESCR90,','on overflow truncate with count) WITHIN GROUP ( ORDER BY C.JPM_DESCR90) from (select unique JPM_DESCR90 JPM_DESCR90
from PS_NPS_LIC_VW_RPT C
where A.EMPLID = F.EMPLID)) JPM
FROM PS_NPS_VIEW_ALL A, (PS_PERSON_NAME B LEFT OUTER JOIN PS_NPS_LIC_VW_RPT C ON B.EMPLID = C.EMPLID ), PSOPRDEFN E
WHERE ( A.EFFDT =
(SELECT MAX(A_ED.EFFDT) FROM PS_NPS_VIEW_ALL A_ED
WHERE A.EMPLID = A_ED.EMPLID
AND A.EMPL_RCD = A_ED.EMPL_RCD
AND A_ED.EFFDT <= SYSDATE)
AND A.EFFSEQ =
(SELECT MAX(A_ES.EFFSEQ) FROM PS_NPS_VIEW_ALL A_ES
WHERE A.EMPLID = A_ES.EMPLID
AND A.EMPL_RCD = A_ES.EMPL_RCD
AND A.EFFDT = A_ES.EFFDT)
AND A.EMPLID = B.EMPLID
AND A.EMPLID = E.EMPLID
AND A.PER_ORG = 'EMP'
AND A.EMPL_STATUS='A'
AND A.PAYGROUP NOT IN ('SUM','CWR'))
GROUP BY A.EMPLID, A.JOBCODE,A.JOBCODE_DESCR, A.EMPL_STATUS, A.LOCATION, A.LOCATION_DESCR, A.NAME, E.EMAILID, B.EMPLID, E.OPRID;
The above syntax gives the following error
Error at Command Line : 3 Column : 44 Error report - SQL Error: ORA-00933: SQL command not properly ended 00933. 00000 - "SQL command not properly ended" *Cause: *Action:
I then tried regex_replace
to remove duplicates.
SELECT A.EMPLID,
RTRIM(REGEXP_REPLACE(
(listagg(Num2,'-') WITHIN GROUP (ORDER BY C.JPM_DESCR90) OVER() ),
'([^-]*)(-\1)+($|-)',
'\1\3'), '-') C.JPM_DESCR90 ,A.JOBCODE,A.JOBCODE_DESCR, A.EMPL_STATUS, A.LOCATION, A.LOCATION_DESCR, A.NAME, E.EMAILID, B.EMPLID, E.OPRID
FROM PS_NPS_VIEW_ALL A, (PS_PERSON_NAME B LEFT OUTER JOIN PS_NPS_LIC_VW_RPT C ON B.EMPLID = C.EMPLID ), PSOPRDEFN E
WHERE ( A.EFFDT =
(SELECT MAX(A_ED.EFFDT) FROM PS_NPS_VIEW_ALL A_ED
WHERE A.EMPLID = A_ED.EMPLID
AND A.EMPL_RCD = A_ED.EMPL_RCD
AND A_ED.EFFDT <= SYSDATE)
AND A.EFFSEQ =
(SELECT MAX(A_ES.EFFSEQ) FROM PS_NPS_VIEW_ALL A_ES
WHERE A.EMPLID = A_ES.EMPLID
AND A.EMPL_RCD = A_ES.EMPL_RCD
AND A.EFFDT = A_ES.EFFDT)
AND A.EMPLID = B.EMPLID
AND A.EMPLID = E.EMPLID
AND A.PER_ORG = 'EMP'
AND A.EMPL_STATUS='A'
AND A.PAYGROUP NOT IN ('SUM','CWR'))
GROUP BY A.EMPLID, CERT, A.JOBCODE,A.JOBCODE_DESCR, A.EMPL_STATUS, A.LOCATION, A.LOCATION_DESCR, A.NAME, E.EMAILID, B.EMPLID, E.OPRID;
And I got the following error:
Error at Command Line : 5 Column : 27 Error report - SQL Error: ORA-00923: FROM keyword not found where expected 00923. 00000 - "FROM keyword not found where expected" *Cause: *Action:
Any suggestions or alternative approaches with sample code would be appreciated.