How to print a dictionary sorted by values?

Question

I need to print a python dictionary that is sorted by values. To sort the dictionary I used this code:

from operator import itemgetter
print(sorted(d.items(), key=itemgetter(1)))

The dictionary is well sorted, but the output is something like this:

[('Apple', '1'), ('Pears', '2'), ('Bananas', '3')]

I'd prefer:

Apple : 1
Pears : 2
Bananas : 3

I tried this wrong code:

dSorted = sorted(d.items(), key=itemgetter(1))
for i in dSorted:
    print(i + " : "+ dSorted[i])

How can I get this result? And, to understand better, when I use (sorted(d.items(), key=itemgetter(1))) the result is no longer a dictionary, but a different data structure, right?

Sorry Scott, I edited the question. Paritosh I found the way to sort the dictionary looking that question, but not how to print it. Thanks for your answers — Lorenzo, Jan 17 '20 at 16:32
Correct, you get a list of tuples. more specifically, `d.items()` itself is a different type of view. you can turn the end result of the sort back into a dictionary by assinging or consuming it accordingly if you're on python 3.6+ After that you can just print as you like. — Paritosh Singh, Jan 17 '20 at 16:32

score 1 · Accepted Answer · answered Jan 17 '20 at 16:34

1

You are iterating a tuple of lists. So just iterate the keys and values and print as you want

dSorted = sorted(d.items(), key=itemgetter(1))
for key,value in dSorted:
        print(key + " : "+ value)

answered Jan 17 '20 at 16:34

tomgalpin

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score -1 · Answer 2 · answered Jan 17 '20 at 16:34

-1

I am assuming you are using a recent version of python (in which dictionaries keep the order), if so, just make another dict out of the sorted list.

sorted_dict = dict(sorted(d.items(), key=itemgetter(1)))
print(sorted_dict)

answered Jan 17 '20 at 16:34

alec_djinn

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How to print a dictionary sorted by values?

2 Answers2