Printing a list with specific seperations

Question

I have been working for a small program that in the end creates a list with 100 randomized numbers in it. I am supposed to print the list in a 10x10 space, and, since I'm a newbie in code I can't really wrap my head around how to do it. Any suggestions?

could look like this:

list1 = [0]*100

and end result should look like this:

[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

Thanks in advance!

What's supposed to happen if you have all zeroes and one item is a 10? Are all entries supposed to be aligned, or do you just want to print one 10-items sublist per line? — Masklinn, Jan 22 '20 at 07:19
Take a look at the [random](https://docs.python.org/3/library/random.html) module — Devesh Kumar Singh, Jan 22 '20 at 07:19
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Have you considered structuring your list as a 10x10 list of lists instead of one 100 items list? This will make the printing super easy — Tomerikoo, Jan 22 '20 at 07:33

score 0 · Answer 1 · answered Jan 22 '20 at 07:25

you can achieve this with two for loops. something like this:

import random
final_list =[]
for i in range(0, 10):
    row_list = []
    for j in range(0, 10):
        row_list.append(random.randint(1, 10000))
    final_list.append(row_list)

break down:

you could use a library called random for creating a random number. you can look at its document here.
in random.randint(1, 10000) I gave a range which is the range of random numbers. you could change it to suit your requirements.
there might be some better way to do this but it's more understandable :)

kederrac · Answer 2 · 2020-01-22T08:54:17.733

0

what you need is just the built-in function print:

print(*(list1[i: i + 10] for i in range(0, len(list1), 10)), sep='\n')

output:

[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

maybe the code is a bit complicated since you are trying to learn but I will try to explain:

there is a generator that splits your initial list into smaller lists of 10 elements:

(list1[i: i + 10] for i in range(0, len(list1), 10))
then I'm using unpack operator * to unpack the generator into print arguments
I'm separating each list by a new line using sep='\n'

a more simple version to achieve your end result is to use a single for loop:

for index in range(0, len(list1), 10):
    print(list1[i: i + 10])

ouptu:

[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

edited Jan 22 '20 at 08:54

answered Jan 22 '20 at 08:06

kederrac

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I sadly dont understand the code so i will not be using this, but still, thanks you for the suggestion and for trying to explain it! – flexan_kodar Jan 22 '20 at 08:37
@flexan_kodar what about now? I added a more simple solution – kederrac Jan 22 '20 at 08:54
Thank you, now it's easier for me to get behind! Im still a lttle confused about what list1[i: i + 10] does but i think i have some general understanding. – flexan_kodar Jan 22 '20 at 09:07
list1[i: i + 10] is using slicing, "cutting" the list at a given start-end position in list, you can have a look here : https://stackoverflow.com/questions/509211/understanding-slice-notation – kederrac Jan 22 '20 at 09:10
I will have a look at that, thank you again for the help! – flexan_kodar Jan 22 '20 at 10:09

score -1 · Answer 3 · answered Jan 22 '20 at 08:33

I have pretty much solved the problem, at least to my satisfacion, it looks like this:

example_list = [0]*100

index_print = 0

for x in range(10):
    for y in range(10):
        print(example_list[index_print], end=' ')
        index_print += 1
    print('\n')

Could be inporved, and i will probably do that too, but right now im satisfied. Sadly i have discovered some problems with my code that i have not solved yet, but thats for anoher question. Thanks for the many answers, would not have expected to get so many on my first post!

rather than print element by element, you could slice the initial list — kederrac, Jan 22 '20 at 10:24

Printing a list with specific seperations

3 Answers3