Memory Garbage on vector.erase of pointer

Question

i would like to know if is safe to do this:

std::vector<int*> v;
...
//no deleting
v.erase(v.begin());

With safe i mean that by doing this, we are not creating garbage, and so that std::vector<T>::erase is calling himself delete pointer;, or if instead i should have done manually the deleting:

std::vector<int*> v;
...
delete v[0];
v.erase(v.begin());

So you basically want to know if `vector` calls `delete` when you use a pointer type? — NathanOliver, Jan 22 '20 at 17:49

Remy Lebeau · Accepted Answer · 2020-01-22T17:52:09.760

1

Standard containers, like std::vector, containing raw pointers DO NOT automatically delete the things that the pointers are pointing at, when removing the pointers from the containers. If you want that, store smart pointers instead, ie std::unique_ptr or std::shared_ptr.

edited Jan 22 '20 at 17:52

answered Jan 22 '20 at 17:50

Remy Lebeau

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ok, thank you so much – Alberto Sinigaglia Jan 22 '20 at 17:51

Memory Garbage on vector.erase of pointer

1 Answers1