use str.split() on every second occurrence of our delimiter

Question

I have a series of varying strings which I need to turn into arrays on every second occurrence of \n, for simplicity please consider the next example:

const str = 'banana\napple\nmango\n3.5'

//I have tried and failed with:

const arr = str.split(/(^\n)+\n(^\n)+/)

// Result should be:
// const arr = ['banana\napple', 'mango\n3.5']

Do I have to use a loop here or what?

Does this answer your question? [Cutting a string at nth occurrence of a character](https://stackoverflow.com/questions/5494691/cutting-a-string-at-nth-occurrence-of-a-character) — Mickael B., Jan 24 '20 at 11:59

score 1 · Accepted Answer · answered Jan 24 '20 at 12:01

1

You could take match instead of split by taking some non breaking character, a breaking character and other non breking character.

const
    string = 'banana\napple\nmango\n3.5',
    result = string.match(/[^\n]+\n[^\n]+/g);
    
console.log(result);

answered Jan 24 '20 at 12:01

Nina Scholz

376,160
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Seryoga · Answer 2 · 2020-01-24T12:15:55.313

1

Damn this is an ugly approach:

 
let t1 = performance.now();

const result = 'banana\napple\nmango\n3.5'
    .split('\n')
    .map((str, i, arr) => (i % 2) === 0 ? str + '\n' + arr[i+1] : null )
    .filter((str) => str !== null);
    
let t2 = performance.now();
console.log(result, t2-t1 + 'μs');

edited Jan 24 '20 at 12:15

answered Jan 24 '20 at 12:07

Seryoga

793
6
15

use str.split() on every second occurrence of our delimiter

2 Answers2