Parsing a requestUrl in Java

Question

I have a request URL i need to parse that URL and have to modify that

EG :if I have request URL like http://www.xyz.com/?a=b&c=d

Now I need to modify the value of c or a to something else before redirecting to this URL How can I achieve this.

Thanks, Ashish

This may help, Ashish http://stackoverflow.com/questions/1667278/parsing-query-strings-in-java — Jim Blackler, May 13 '11 at 12:38
See this question on parsing URLs is java, there are a number of possibilities: http://stackoverflow.com/questions/1667278/parsing-query-strings-in-java — Richard H, May 13 '11 at 12:39

score 1 · Accepted Answer · edited May 13 '11 at 13:01

Here is what you can do:

 public static Map<String, String> getQueryMap(String query)
    {
        String[] params = query.split("&");
        Map<String, String> map = new HashMap<String, String>();
        for (String param : params)
        {
            String name = param.split("=")[0];
            String value = param.split("=")[1];
            map.put(name, value);
        }
        return map;
    }

    String query = url.getQuery();  
    Map<String, String> map = getQueryMap(query);  
    Set<String> keys = map.keySet();  
    for (String key : keys)  
    {  
       System.out.println("Name=" + key);  
       System.out.println("Value=" + map.get(key));  
    }

This looks fine in this way I am able to modify the content of that URL .But how can I get again get the URL from this map with modified value — Ashish Sharma, May 16 '11 at 06:42

score 0 · Answer 2 · answered May 13 '11 at 12:49

0

invoke request.getParameterMap and iterate over the querystring keys and replace with what ever needed

answered May 13 '11 at 12:49

Surya Chaitanya

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Parsing a requestUrl in Java

2 Answers2