How can I match strings except for another string pattern in regex?

Asked Jan 28 '20 at 22:02

Active Jan 28 '20 at 22:02

Viewed 15 times

How can I match strings without another string?

Example strings:

foo bar qux    Expected Result: MATCH    (`foo` & `bar` without `skip` or `ignore`)
foo            Expected Result: NO MATCH (`foo`, without `bar`)
bar baz qux    Expected Result: NO MATCH (`bar`, without `foo`)
foo bar skip   Expected Result: NO MATCH (`foo` & `bar`, but also `skip`)
ignore foo bar Expected Result: NO MATCH (`foo` & `bar`, but also `ignore`)
baz qux        Expected Result: NO MATCH (not `foo` & `bar`)

Regex:

/(?=.*?\bfoo\b)(?=.*?\bbar\b)((?!skip|ignore).)*$/gi

Here's a Regexr sandbox: https://regexr.com/4t4lo

Yes, there are several similar questions, but nothing I've been able to work into this simple sandbox.

asked Jan 28 '20 at 22:02

Ryan

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Use `^(?=.*\bfoo\b)(?=.*\bbar\b)(?!.*(skip|ignore)).*$` – Wiktor Stribiżew Jan 28 '20 at 22:05
Thanks @WiktorStribiżew. Does that work for you in regexr? I cannot get it to match the expected results above. – Ryan Jan 28 '20 at 22:09
@WiktorStribiżew, the proposed answer does not get me any closer to answering this question. Did I miss something? – Ryan Jan 28 '20 at 22:10
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It fully answers your question. You missed `.*` in the negative lookahead and a `^` anchor at the start. [Works wonders](https://regex101.com/r/wZdM0v/1). – Wiktor Stribiżew Jan 28 '20 at 22:13
Thanks. Also I had `gi` instead of `gm`. – Ryan Jan 28 '20 at 22:23

How can I match strings except for another string pattern in regex?

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