Code:
date = [item.find(class_='wr-date__light').get_text() for item in items]
Ouput:
['31st\xa0January', '1st\xa0February', '3rd\xa0February', '4th\xa0February', '5th\xa0February', '6th\xa0February', '7th\xa0February', '8th\xa0February']
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Yam Mesicka
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gogulcv
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1 Answers
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You can use string replacement to remove the characters. And you can use map to apply that to every element of the list.
date = list(map(lambda s: s.replace('\xa0', ''), date))
If you are not comfortable using lambda expressions, you can define a new function.
def replace(text):
return text.replace('\xa0', '')
date = list(map(replace, date))
jkr
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Why do you need to do all these when you can simply write this `date = [item.find(class_='wr-date__light').get_text().replace('\xa0','') for item in items]` right? – Ch3steR Jan 30 '20 at 20:24
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\xa0 is a non breaking space in latin1 so it should be replaced with space – ElmoVanKielmo Jan 30 '20 at 20:26
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https://stackoverflow.com/users/12416453/ch3ster thanks – gogulcv Jan 30 '20 at 20:30