How to remove a variable out of a list of variables in prolog?

Question

I wanna implement the DPLL algorithm. Therefore i have to remove all occurrencies of a variable in a list of other variables, e.g. deleting neg(X) out of [neg(X), pos(X), neg(Y), pos(Y)] should return [pos(X), neg(Y), pos(Y)]. I've tried some built-in predicates like exclude/3 or delete/3 but all left me with asuming X = Y and a result [pos(X), pos(Y)], with all neg(_) removed, but I only want neg(X) removed and not neg(Y). Is this somehow possible?

Why don't you call your variables with lowercase letter? – damianodamiano Jan 31 '20 at 14:57 — damianodamiano, Jan 31 '20 at 14:57

score 0 · Accepted Answer · answered Jan 31 '20 at 16:31

From the Logtalk library list object:

delete([], _, []).
delete([Head| Tail], Element, Remaining) :-
    (   Head == Element ->
        delete(Tail, Element, Remaining)
    ;   Remaining = [Head| Tail2],
        delete(Tail, Element, Tail2)
    ).

Sample call:

?- delete([neg(X), pos(X), neg(Y), pos(Y)], neg(X), Rest).
Rest = [pos(X), neg(Y), pos(Y)].

The key is to use the standard ==/2 term equality predicate instead of the standard =/2 unification predicate.

How to remove a variable out of a list of variables in prolog?

1 Answers1