How resolve this issue? def _create_frequency_table(text_string)->dict: ^ SyntaxError: invalid syntax

Asked Jan 31 '20 at 12:56

Active Mar 23 '20 at 19:49

Viewed 460 times

This is the part of the code:

'''
Don’t leave your dreams to chance.
'''


def _create_frequency_table(text_string) -> dict:
    """
    we create a dictionary for the word frequency table.
    For this, we should only use the words that are not part of the stopWords array.

    Removing stop words and making frequency table
    Stemmer - an algorithm to bring words to its root word.
    :rtype: dict
    """
    stopWords = set(stopwords.words("english"))
    words = word_tokenize(text_string)
    ps = PorterStemmer()

This is the part of code I'm trying to understand.. and below is the error.

line 29
    def _create_frequency_table(text_string) -> dict:
                                             ^
SyntaxError: invalid syntax

Any help will be greatly appreciated,

edited Mar 23 '20 at 19:49

eyllanesc

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asked Jan 31 '20 at 12:56

Rakesh Kumar

What python version are you using? – GPhilo Jan 31 '20 at 13:00
I'm using python 2.7 – Rakesh Kumar Jan 31 '20 at 13:07
3

type hints (i.e., the `-> dict` part of you function definition there) were introduced in python 3.5, Python 2.7 won't understand them and give a syntax error. – GPhilo Jan 31 '20 at 13:08
1

Does this answer your question? [Type hinting in Python 2](https://stackoverflow.com/questions/35230635/type-hinting-in-python-2) – GPhilo Jan 31 '20 at 13:08
Guido van Rossum says python2 gonna die: https://www.youtube.com/watch?v=7kn7NtlV6g0 – Susan Jan 31 '20 at 13:15

How resolve this issue? def _create_frequency_table(text_string)->dict: ^ SyntaxError: invalid syntax

0 Answers0