Need to make a list by splitting the given string in python

Question

Input string has 'n' times of X. Like this "XXXXX" Need to split the string and make out a list in which each character of the string(X) is each element of list.

Constraints:
0 <= X <= any number
'n' is unknown

Example 1: X is 12,

Input string : "121212121212121212"
Output list : [12,12,12,12,12,12,12,12,12]

Example 2: X is 2,

Input string : "2222"
Output list : [2,2,2,2]

Example 3: X is 489,

Input string : "489489489"
Output list : [489,489,489]

I tried this approach my_list = list(input_string)

I am getting output like, [1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2]

Can anyone help me to resolve this?

Edit 1: I am new to stackoverflow. Please help me to edit this question properly.

Edit 2: As this question is clear and understandable, please consider upvoting.

Does this answer your question? [Find the repeating substring a string is composed of, if it exists](https://stackoverflow.com/questions/43035406/find-the-repeating-substring-a-string-is-composed-of-if-it-exists) — DarrylG, Feb 01 '20 at 14:26
Please clarify your question if possible. Do you want to generate two-character pairs in a list always? Or, do you want to break up a string into like sequences of characters? E.g. would `123123` become `[123, 123]`, or would it become `[12, 31, 23]` ? — Tim Biegeleisen, Feb 01 '20 at 14:35
Since X is known as to the latest edit, my answer below should work. — myke, Feb 01 '20 at 14:49

Moo De · Accepted Answer · 2020-02-01T14:38:20.787

3

To decode this string you need 'n' and X anyway. Why not build it directly with:

li = [X] * n

Edit: If you don't have 'n', you could get it easily from the given string. (Under the condition that givenString only consist of X)

n = len(givenString) / len(str(X))
li = [X] * n

edited Feb 01 '20 at 14:38

answered Feb 01 '20 at 14:25

Moo De

46
3

I don't know "n" beforehand. – surya Feb 01 '20 at 14:29

score 2 · Answer 2 · edited Feb 01 '20 at 14:53

2

You can use regular expressions:

import re 

x = input('Enter Your X : ')
mystr = input('Enter Your Input String : ')

result = re.findall(x, mystr) 
print(result)

This outputs:

Enter Your X : 12
Enter Your Input String : 121212121212
['12', '12', '12', '12', '12', '12']

edited Feb 01 '20 at 14:53

Tomerikoo

18,379
16
47
61

answered Feb 01 '20 at 14:31

Fuji Komalan

1,979
16
25

myke · Answer 3 · 2020-02-01T14:53:34.617

1

Here's a variant that makes sure the substrings all match the given pattern:

input_ = "121212121212121212"
x = "12"
res = []
while input_.startswith(x):
    res.append(x)
    input_ = input_[len(x):]

edited Feb 01 '20 at 14:53

answered Feb 01 '20 at 14:22

myke

479
3
14

score 1 · Answer 4 · answered Feb 01 '20 at 14:59

If X is also unknown, you can use this:

import textwrap

def find_shortest_pattern(input_):
     for len_ in range(1, int(len(input_) / 2) + 1):
          patterns = textwrap.wrap(input_, len_)
          if all(pattern == patterns[0] for pattern in patterns):
               return patterns[0]

find_shortest_pattern("123123123")

Need to make a list by splitting the given string in python

4 Answers4