How can I pick a random word in from a list in a loop?

Question

Hello I am a learning python and my question is I have some words in a list I want to randomly select a word using a loop. Every time I run this code below it returns only random single letters like "y n d"

import random
import time

randomwords = ["my", "random", "words"]

for x in randomwords:
    time.sleep(1)
    print(random.choice(x))

how can I make the code return random order of the words like "words" "my" "random"

Does this answer your question? [Best way to randomize a list of strings in Python](https://stackoverflow.com/questions/1022141/best-way-to-randomize-a-list-of-strings-in-python) — CDJB, Feb 05 '20 at 11:34
This method, even when corrected can print the same word twice. You need to shuffle the list — clubby789, Feb 05 '20 at 11:39

score 2 · Accepted Answer · answered Feb 05 '20 at 11:35

2

random.choice(x) will choose from x, and x is an individual word from randomwords.

If you want to choose from randomwords, do it:

for x in randomwords:
    time.sleep(1)
    print(random.choice(randomwords))

answered Feb 05 '20 at 11:35

ForceBru

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Thank you this worked out for me and im new to stack overflow my answer was answered fast thank you. – Jean loriston Feb 05 '20 at 11:39

ruohola · Answer 2 · 2020-02-05T11:41:20.543

You can use random.shuffle for this:

import random
import time

randomwords = ["my", "random", "words"]

for choice in random.shuffle(randomwords):
    time.sleep(1)
    print(choice)

The reason why your original code didn't work the way you wanted, is that x will be assigned to each of the list elements in turn. So on the first cycle x = "my", and then you print a random character from that string with random.choice(x), which will result in either m or y.

How can I pick a random word in from a list in a loop?

2 Answers2