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$ cat file.txt | head -n10
icmp_seq=1 ttl=128 time=50.0 ms
icmp_seq=2 ttl=128 time=51.9 ms
icmp_seq=3 ttl=128 time=50.9 ms
icmp_seq=4 ttl=128 time=49.9 ms

$ cat file.txt | grep -v 'time=5 . ms' | head -n 5
icmp_seq=1 ttl=128 time=50.0 ms
icmp_seq=2 ttl=128 time=51.9 ms
icmp_seq=3 ttl=128 time=50.9 ms
icmp_seq=4 ttl=128 time=49.9 ms

I want it like this with all lines with "time=5X.XXms" ​​excluded:

$ cat file.txt | grep -v "time=5 . ms" | head -n 5
icmp_seq=4 ttl=128 time=49.9 ms
John Kugelman
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Gustavo
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1 Answers1

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I think you can use [0-9] for X, which would give the following regular expression:

time=5[0-9].[0-9][0-9] ms

So you get following command:

cat file.txt | grep -v "time=5[0-9].[0-9][0-9] ms" | head -n 5
Dominique
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    should be just one `[0-9]` after the `.` character.. can also use `grep -m5 -v 'time=5[0-9].[0-9] ms' file.txt` to do it in one command instead of three – Sundeep Feb 07 '20 at 14:19
  • Perfect! I just added the space: cat file.txt | grep -v 'time=5[0-9].[0-9] \ms' Thanks – Gustavo Feb 07 '20 at 14:19
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    Note that `.` will match any character unless quoted. – stark Feb 07 '20 at 15:03
  • The [`cat` is useless](/questions/11710552/useless-use-of-cat) and the `head` can be avoided with `grep -m 5` – tripleee Feb 18 '20 at 13:27