Removing object properties with empty values from JS object

Question

Is there a way to loop over an object and remove properties where the value matches a certain condition? In this case, I want to remove any properties that have no value.

Here is what I have:

var user = { first : 'John', last : 'Doe', city : 'Boston', state : 'MA', zip : '', birthdate : ''}

for(const [key, value] of Object.entries(user)){
  if(!value){
    delete user.key;
   }
 });

The code is detecting an empty value, but the delete function is not working;

Thanks!

@Pierre OP is iterating over the return value of `Object.entries()` not the object itself — Andreas, Feb 07 '20 at 14:34
try this: delete user[key]; https://codesandbox.io/s/compassionate-yonath-crtit — Mukesh, Feb 07 '20 at 14:36
`key` has the name of the property. You have to use bracket notation to access the property with that name -> `user[key]` — Andreas, Feb 07 '20 at 14:36

score 0 · Answer 1 · answered Feb 07 '20 at 14:34

0

Reflect.deleteProperty(user, key);

you can use something like this

answered Feb 07 '20 at 14:34

Siva K V

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score 0 · Accepted Answer · answered Feb 07 '20 at 14:37

You were almost there, try like so:

var user = { first : 'John', last : 'Doe', city : 'Boston', state : 'MA', zip : '', birthdate : ''};

for (let [key, value] of Object.entries(user)) {
  if(value.length <= 0) {
      delete user[key]
  }
}
console.log(user);

Removing object properties with empty values from JS object

2 Answers2