Try catch not working in Laravel 5.6 when a number is divided by zero

Question

Try catch block can not prevent run time exception in my Laravel code. I wrote following code to test the exception handling:

try{
    $a=112/0;
}catch(Exception $e){
    $a=99;
}

But it returns a Run time error. Please help me to solve the issue.

It's a warning, not an exception. Run a simple test `if ($dividor === 0) { $a = 99; }` — Qirel, Feb 15 '20 at 12:34
@Qirel then why this solution worked for me ? try{ $a=112/0; }catch(\Exception $e){ $a=99; } — Hafijur Rahman Sakib, Feb 15 '20 at 12:48
@HafijurRahmanSakib Because Laravel turns all PHP warnings into ErrorException Instance. Check this out: [Illuminate/Foundation/Bootstrap/HandleExceptions.php](https://github.com/laravel/framework/blob/5.3/src/Illuminate/Foundation/Bootstrap/HandleExceptions.php#L27-L42) — Qumber, Feb 15 '20 at 13:07

Qumber · Answer 1 · 2020-02-15T12:53:16.243

2

Try this:

try{
    $a=112/0;
}catch(\Exception $e){
    $a=99;
}

Notice the \ before Exception.

Update: As @Qirel suggests:

You can simply update your code to do it without try/catch:

if($d === 0){
    $a = 99;
} else{
    $a = 112/$d
}

edited Feb 15 '20 at 12:53

answered Feb 15 '20 at 12:30

Qumber

1

You can't do it with a try/catch to begin with, because its not an exception. – Qirel Feb 15 '20 at 12:43
@Qirel Looks like, in case of Laravel, you can. See this: https://stackoverflow.com/questions/40548258/how-laravel-handles-php-warnings – Qumber Feb 15 '20 at 13:09

score 0 · Answer 2 · answered Feb 15 '20 at 12:32

0

Because you are using php7 you need to use Throwable to catch the exception like this:

try{
    $a=112/0;
}catch(Exception $e){
    // For php 5
    $a=99;
} catch(\Throwable $e) {
// For php7
    $a=99;
}

answered Feb 15 '20 at 12:32

TsaiKoga

2 Answers2