Java Pattern.matches() returns wrong result

Asked Feb 15 '20 at 20:29

Active Feb 15 '20 at 20:29

Viewed 77 times

I tried the code below in Java but I think its wrong:

import java.util.regex.Pattern;


public class Main {

    public static void main(String[] args) {
        System.out.println(Pattern.matches("[A-z]+", "1d"));
        System.out.println(Pattern.matches("[0-9]+", "1d"));
        System.out.println(Pattern.matches("[A-z]+", "1"));
        System.out.println(Pattern.matches("[0-9]+", "d"));
    }
}

And I expected this output:

true
true
false
false

but I got this output:

false
false
false
false

Why is the output of Java wrong?

asked Feb 15 '20 at 20:29

Grevak

2

`matches` is not a search, it needs to match the entire expression – njzk2 Feb 15 '20 at 20:33
Also, [Regex to match only letters](//stackoverflow.com/a/3617808) – 001 Feb 15 '20 at 20:34
Your regexs are not correct, what you want to achieve exactly – Youcef LAIDANI Feb 15 '20 at 20:39
The regex isn't wrong. Pattern.matches() only does not do what I have expected – Grevak Feb 15 '20 at 20:53

Java Pattern.matches() returns wrong result

0 Answers0