Splitting words in a list

Question

How to split a list into separate words. I know that you can split strings with split but I need to split a list.

Here is my code:

text = ['a,b', 'c,d']
text = text.replace(',', ' ')
for i in text:
  print(text.split())

When I run it, an error pops up and when I try to convert the list into a string there are random extras like \n, ' and [] that shouldn't be there.

Expected result: I want the outcome to be a list that contains ['a', 'b', 'c', 'd'] that when I print, comes up with that.

The error comes up on line two and says:

AttributeError: 'list' object has no attribute 'replace'

Answer 1

Well you can do that easily but first you should read what does the split function exactly do.

newList = []
for i in text:
    words = i.split(',')
    newList.extend(words)
print(newList)

Here are some useful information, Python list extend, Iterating over a list.

Plus, There is no method called replace for lists, this method works for Strings.

Answer 2

your_list = [ x for sublist in text for x in sublist.split(',') ]

Answer 3

There is no replace function for a list. I guess what you want is to split on comma:

text = ['a,b', 'c,d']
result = []
for i in text:
  result.extend(i.split(','))

Note the second change I did is to print i - the thing that iterates as opposed to the whole text. Additionally I am calling extend on the result to produce a single list.

Answer 4

One more approach:

text = ['a,b', 'c,d']
text = ','.join(text)
text = text.split(',')
print(text)
# ['a', 'b', 'c', 'd']

Answer 5

You could do to the following:

text = ['a,b', 'c,d']
text_str = "".join(text).replace(",", "")
arr = [c for c in text_str]

its a bit verbose, but those are the steps

Answer 6

Maybe this?

>>> from itertools import chain
>>> text = ['a,b', 'c,d']
>>> list(chain(*[item.split(',') for item in text]))
['a', 'b', 'c', 'd']