Checking if an array of objects contains value without looping?

Question

Right now I have an array that looks like this

    const array = [
    {
      value: 'received',
      title: 'Hjá Birgja',
    },
    {
      value: 'pending',
      title: 'Yfirstandandi',
    },
    {
      value: 'processing',
      title: 'Í vinnslu',
    },
  ]

and I would like this to return true

if(array.includes('processing'){
  // do something
}

Why not just make a looping function somewhere and just call that? Then you don't have to write a new loop in your code each time -- just call your function that packages up that logic. — Jeremy Harris, Feb 21 '20 at 13:48
`array.includes('processing')`: the array don't include `processing`, it's one of its object that contains, you need to loop over the objects and find if one of them have in its value the "processing" — Calvin Nunes, Feb 21 '20 at 13:50

score 0 · Answer 1 · answered Feb 21 '20 at 13:49

0

not exactly what you wanted since i'm not sure if you only wanted to search the value key but here's a solution

if (array.find(i => i.value === 'processing')) {
  // do something
}

answered Feb 21 '20 at 13:49

Gene Sy

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Was hoping I could do it without having to loop but great solution. Always forget about .find – meowzart Feb 21 '20 at 13:58
Yeah atleast this stops at the first thing it finds instead of continuing – Gene Sy Feb 21 '20 at 14:00

Checking if an array of objects contains value without looping?

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