Hi new to python and programming in general I'm trying to find an element in an array based on user input here's what i've done
a =[31,41,59,26,41,58]
input = input("Enter number : ")
for i in range(1,len(a),1) :
if input == a[i] :
print(i)
problem is that it doesn't print out anything. what am I doing wrong here?
input returns a string. To make them integers wrap them in int.
inp=int(input('enter :'))
for i in range(0,len(a)-1):
if inp==a[i]:
print(i)
Indices in list start from 0 to len(list)-1.
Instead of using range(0,len(a)-1) it's preferred to use enumerate.
for idx,val in enumerate(a):
if inp==val:
print(idx)
To check if a inp is in a you can this.
>>> inp in a
True #if it exists or else False
You can use try-except also.
try:
print(a.index(inp))
except ValueError:
print('Element not Found')
input returns a string; a contains integers.
Your loop starts at 1, so it will never test against a[0] (in this case, 31).
And you shouldn't re-define the name input.
Please don't declare a variable input is not a good practise and Space is very important in Python
a =[31,41,59,26,41,58]
b = input("Enter number : ")
for i in range(1,len(a),1):
if int(b) == a[i] :
print(i)
I think you want to check a value from your list so your input need to be a Int. But input takes it as String. That's you need to convert it into int.
input is providing you a str but you are comparing a list of ints. That and your loop starts at 1 but your index starts at 0
