!= sign is being ignored?

Question

I know I am being stupid but I am not sure how. For this program, the user must enter 1 or 2, 1 converts Inches to CM, and 2 converts CM to Inches.

Now the problem is, if they enter a number that is not equal to 1 or 2, it should display that error "Sorry, please enter either 1 or 2". Although the error message displays when the user doesn't enter 1 or 2, when I enter the correct inputs 1 or 2, it displays that error anyway.

Any solutions? Thanks

ask_user = int(input("Enter 1 to convert inches to centimetres or 2 to convert centimetres to inches: "))

#This is the error below, it prints this statement when you enter 1 or 2**
if ask_user != 1 or 2:
    print("Sorry, please enter either 1 or 2!")

if ask_user == 1:
    inch = int(input("Enter the amount of Inches you wish to convert to Centimeter: "))
    cm = inch * 2.54
    print(cm)

if ask_user == 2:
    cm = int(input("Enter the amount of Centimeter you wish to convert to Inch(s): "))
    inch = cm * 0.393701
    print(inch)

`if ask_user not in (1, 2):` – Klaus D. Feb 26 '20 at 02:26 — Klaus D., Feb 26 '20 at 02:26

James · Answer 1 · 2020-02-26T02:34:31.693

0

if ask_user != 1 and ask_user != 2:
    print("Sorry, please enter either 1 or 2!")
    return

edited Feb 26 '20 at 02:34

answered Feb 26 '20 at 02:26

James

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it's wrong! Look: `ask_user=1` then: `1 != 1`? FALSE, then: `1 != 3`? TRUE. So... – felipsmartins Feb 26 '20 at 02:30

!= sign is being ignored?

1 Answers1