Array and pointer differences

Asked Feb 28 '20 at 17:33

Active Feb 28 '20 at 17:33

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In a C program, suppose I have a char array and a char pointer.

char word[6] = "HELLO";
word[1] = 'A';

char * word = "HELLO";
word[1] = 'A';

Why cant't we update the word using the 2nd method but can with 1st?

Note: Using 2nd method, though the program compiles there is a

Segmentation fault

error.

asked Feb 28 '20 at 17:33

arnieM

Because in the second example you are trying to modify a "string literal" which is read-only. – Weather Vane Feb 28 '20 at 17:35
1

Does this answer your question? [String literals: pointer vs. char array](https://stackoverflow.com/questions/12795850/string-literals-pointer-vs-char-array) – UnholySheep Feb 28 '20 at 17:35
1

Please see[Why Can I not modify a string literal in c?](https://stackoverflow.com/questions/58584310/why-can-i-not-modify-a-string-literal-in-c) – Weather Vane Feb 28 '20 at 17:37
Closing with another duplicate. – Weather Vane Feb 28 '20 at 17:38
@UnholySheep Thanks a lot. Excellent suggestion. – arnieM Feb 28 '20 at 17:39

0 Answers0