Dynamically spawn 'X' number of queues in python

Question

i need to spawn 'x' number of queues in python

q1 = Queue(maxsize = 0)
q2 = Queue(maxsize = 0)
.
.

qn = Queue(maxsize = 0)

what is the pythonic way to do it ?

List of `Queue`s? by the way `maxsize=0` is the default. – Guy Mar 01 '20 at 12:28 — Guy, Mar 01 '20 at 12:28

CC7052 · Answer 1 · 2020-03-01T12:45:40.367

0

Edited:

for i in range(10):
    locals()["q" + str(i)] = Queue(maxsize=0)

print(q1)

Output:

<queue.Queue object at 0x00000163554B6220>

edited Mar 01 '20 at 12:45

answered Mar 01 '20 at 12:30

CC7052

on doing that i get a ``` [, , ]``` i need somehitng like q1 = queue object, q2 = queue object and so on – omkar joglekar Mar 01 '20 at 12:31
yeah if you want to use one of them you can access by `q[n]`. helpful? – CC7052 Mar 01 '20 at 12:32
i could but something like queue_txmessages , queue_rxmessages, queue_dropped messages makes better sense in my script i think hence i wanted them assigned to individual variables instead in a list – omkar joglekar Mar 01 '20 at 12:35
updated, is that what you want? @omkarjoglekar – CC7052 Mar 01 '20 at 12:46
1

The documentation for [`locals()`](https://docs.python.org/3/library/functions.html#locals) clearly states it should not be modified. – martineau Mar 01 '20 at 13:02
@CC7052 i think it does the job :) thanks – omkar joglekar Mar 01 '20 at 13:09
@martineau what would be the implications of this ? after modifying the locals () ? – omkar joglekar Mar 01 '20 at 13:09

1 Answers1