Having trouble on making a yes or no question

Question

I'm trying to make a yes or no question in which yes would equal the value(DEFAULT_OVERTIME_MULTIPLIER) and no would direct you to input any value want between 0 and 3; the yes portion works, but the no portion doesn't. What am I missing on this?

def get_multiplier():
    chosen_multiplier = -1

    while chosen_multiplier == input("Default multiplier is 1.5, Do you want that? (yes or no):"):
        if chosen_multiplier == "yes" or "Yes":
            chosen_multiplier = DEFAULT_OVERTIME_MULTIPLIER
        elif chosen_multiplier = "no" or "No":
            chosen_multiplier < MINIMUM_OVERTIME_MULTIPLIER or chosen_multiplier > MAXIMUM_OVERTIME_MULTIPLIER
            chosen_multiplier = float(input("Between 0 and 3, what is your overtime multiplier value? (Default is 1.5):" ))
        else:
            chosen_multiplier < MINIMUM_OVERTIME_MULTIPLIER or chosen_multiplier > MAXIMUM_OVERTIME_MULTIPLIER
            print("Invalid value, the overtime multiplier is between 0 and 3.")
    return chosen_multiplier

See, for instance, [How to test multiple variables against a value?](https://stackoverflow.com/questions/15112125/how-to-test-multiple-variables-against-a-value) — khelwood, Mar 01 '20 at 20:30

miszcz2137 · Answer 1 · 2020-03-01T20:39:04.183

0

You have single equality sign in line 7. Also you can't assign value in condition. What's more lines 8 and 11 don't do anything chosen_multiplier < MINIMUM_OVERTIME_MULTIPLIER or chosen_multiplier > MAXIMUM_OVERTIME_MULTIPLIER.

while True:
    choose = input("Default multiplier is 1.5, Do you want that? (yes or no):")
    if choose == "yes" or "Yes":
        chosen_multiplier = DEFAULT_OVERTIME_MULTIPLIER
    elif chosen_multiplier = "no" or "No":
        chosen_multiplier = float(input("Between 0 and 3, what is your overtime multiplier value? (Default is 1.5):" ))
    if chosen_multiplier < MINIMUM_OVERTIME_MULTIPLIER or chosen_multiplier > MAXIMUM_OVERTIME_MULTIPLIER:
        print("Invalid value, the overtime multiplier is between 0 and 3.")
    else:
        break

That may not do exactly what you want, but that's as much as I can understand and should give you some ideas.

edited Mar 01 '20 at 20:39

answered Mar 01 '20 at 20:31

miszcz2137

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i did that but still no good – El macho chacho Mar 01 '20 at 20:35
if you "***did that***", update your question. and "***still no good***", doesn't help anyone, **be specific**. – Pedro Lobito Mar 01 '20 at 20:37
how about this, does it make sense that i have two inputs in that function? – El macho chacho Mar 01 '20 at 21:05
If you want additional information from user then it's very sensible. – miszcz2137 Mar 01 '20 at 21:09

Having trouble on making a yes or no question

1 Answers1