How to access the name of a JSON object?

Question

I have this JSON returned me from Firebase Realtime Database.

{
       "betslipid-4322": {
            "amount": 100,
            "bets": [
                {
                    "betType": "FT_RESULT_0",
                    "matchid": "ts-fb",
                    "odd": 2.4,
                    "status": "WAITING"
                }
            ],
            "status": "WAITING"
        },
        "betslipid-4323": {
            "amount": 7.5,
            "bets": [
                {
                    "betType": "FT_RESULT_2",
                    "matchid": "gs-fb",
                    "odd": 2.7,
                    "status": "WAITING"
                },
                {
                    "betType": "FT_RESULT_1",
                    "matchid": "gs-gb",
                    "odd": 1.3,
                    "status": "WAITING"
                }
            ],
            "status": "WAITING"
        }
}

I want to place the attributes of this JSON (including the betSlipID at the beginning) to the following Java class.

public class BetSlip {

    private List<Bet> bets;

    private Float amount;

    private BetStatus status;

    private betSlipID;
}

However, I was unable to access the betSlipIDs which are "betslipid-4322" and "betslipid-4323" in this case and I was also unable to convert the JSON to my java class by the following code.

private RestTemplate restTemplate = new RestTemplate();
List<BetSlip> betSlip = restTemplate.getForObject(getDatabaseLink("incomplete-betslips"), ArrayList.class);

Note that I don't know the betSlipIDs when I get the JSON response, so I can't create another class which includes a variable named the incoming betSlipID.

You can create a class which hold List. and map on that parent class — Noshaf, Mar 03 '20 at 11:38
@Noshaf I already tried that but that doesn't help me getting betSlipIDs — , Mar 03 '20 at 11:40

score 2 · Answer 1 · answered Mar 03 '20 at 12:16

2

I am not saying this is optimal, but you can follow this to do your task as your betslipid-x is variable, I am describing the steps to be followed only:

just return a json object from your restTemplate see Spring restTemplate get raw json string
get the keys applying keySet() on your returned json and you will get all your betslipid-x
based on that, get associated object of that key and deserialize in your BetSlip class and set the key as betSlipID.
Thus you get your desired object.

This should do your job.
Let me know if your need further clarification.

answered Mar 03 '20 at 12:16

user404

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Thanks, this is almost exactly how I solved. I am accepting your answer but those needing code example of what you describe here can have a look at my answer. – Mar 03 '20 at 12:22
that's right, theory here and code is in your answer :D ! – user404 Mar 03 '20 at 13:56

score 0 · Accepted Answer · answered Mar 03 '20 at 12:14

Following @Noshaf 's comment here is the solution:

HashMap<String,BetSlip> betSlipWithoutID = restTemplate.getForObject(getDatabaseLink("incomplete-betslips"), HashMap.class);

After creating this HashMap, now there is a need for creating BetSlip class with betSlipID:

ObjectMapper mapper = new ObjectMapper();

BetSlip betSlip = mapper.convertValue(betSlipWithoutID.get(betSlipWithoutID.keySet().iterator().next()), BetSlip.class);

betSlip.setBetSlipID(betSlipWithoutID.keySet().iterator().next());

Here we go, betSlip is ready for use with a betSlipID attribute is set.

How to access the name of a JSON object?

2 Answers2