$pattern = "/(?i)\b((?:https?:\/\/|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}\/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))/";
$str = file_get_html($_GET['url'])->plaintext;
if($num_found = preg_match_all($pattern, $str, $out)) {
print_r($out[0]);
}
Output
Array ([0] => https://ssl.gstatic.com/gb/images/b_8d5afc09.png [1] => https://ssl.gstatic.com/gb/images/b8_3615d64d.png [2])
So now I want to find if any of the following links contains some specific word let's say this 'b_8d5afc09' and then i want to take that link and display that link only.
So far i have tried out using 'in_array' but it never finds even if the link even exists, am i doing something wrong? Any suggestions appreciated!!
if (in_array("b_8d5afc09", $out[0]))
{
echo "found";
}
else
{
echo "nope";
}