How do I correctly get the value of 'ⅻ' (and other similar non-alphabetical characters) and store it in a string?

Question

Given a character that is not a standard alphabet character, such as 'ⅻ', I'm having problems converting it to a string and retaining it's value. For example If I have:

String myStr = "ⅻⅾ℡ℬ";
Character myChar = myStr.charAt(0);

Then System.out.println('ⅻ' == myChar); returns true, whereas System.out.println("ⅻ" == Character.toString(myChar)); returns false.

Thus my question effectively is how do I correctly get the value of 'ⅻ' and store it in a string?

Well, you wouldn't compare `String`s in java with `==`. – sleepToken Mar 04 '20 at 13:50 — sleepToken, Mar 04 '20 at 13:50

score 1 · Accepted Answer · answered Mar 04 '20 at 13:52

1

Both of these conditions return true:

public class Test {
    public static void main(String args[]) {
        String myStr = "ⅻⅾ℡ℬ";
        Character myChar = myStr.charAt(0); 

        System.out.println('ⅻ' == myChar);
        System.out.println("ⅻ".equals(Character.toString(myChar))); 
    }
}

answered Mar 04 '20 at 13:52

sleepToken

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so `(Character.toString(myChar)` does actually contain "ⅻ"? – Anya Mar 04 '20 at 13:55
@Anya yes, `.equals()` tests for value equality. Similarly, if you called `System.out.println(Character.toString(myChar));`, the result would be `ⅻ`. – sleepToken Mar 04 '20 at 14:00

How do I correctly get the value of 'ⅻ' (and other similar non-alphabetical characters) and store it in a string?

1 Answers1