Function call does not change value

Question

def divide_by_2(number):
   number /= 2

...

def main():
    n = 42
    divide_by_2(n)
    print(n)

The result is 42, not 21. Why is this the case? Thanks in advance.

Variables don't work like that in python: https://nedbatchelder.com/text/names.html — quamrana, Mar 06 '20 at 14:30

score 3 · Answer 1 · answered Mar 06 '20 at 14:29

3

You have to return the value from your function

def divide_by_2(number):
   return number / 2 # return the calculation


...

def main(n):
    n = divide_by_2(n)
    print(n)
    >> 21

main(42) # call main with variable number

answered Mar 06 '20 at 14:29

Meshi

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Function call does not change value

1 Answers1