How to do this simple weighted average in LINQ?

Question

I'm just curious if this could be done in a single LINQ statement. I need to do a simple weighted average like this:

IEnumerable<double> values = { v0, v1, v2, v3, ...}
WeightedAverage = (((v0 + v1) / 2 + v2) / 2 + v3) / 2 ...

possible duplicate of [Weighted Average with LINQ](http://stackoverflow.com/questions/2714639/weighted-average-with-linq) — Dmitry Pavlov, Mar 12 '14 at 11:29

score 7 · Accepted Answer · answered May 19 '11 at 14:02

7

double average = values.Aggregate((x, y) => (x + y) / 2.0);

answered May 19 '11 at 14:02

dlev

1 Answers1