php preg_match or php regex to find word

Question

how can I write some preg_match() or any other condition to find whether the URL have "php" in the second place. Eg url below "http://a.com/php/abcpdf/".

If the URL have "/php/" in the second place my condition should execute else not.

Does this answer your question? [PHP preg match \*.domain.com or \*.domain.co.uk](https://stackoverflow.com/questions/7782591/php-preg-match-domain-com-or-domain-co-uk) — Rashid 'Lee' Ibrahim, Mar 09 '20 at 22:16

score 0 · Answer 1 · answered Mar 09 '20 at 18:23

0

this should match what you need

preg_match("#^/php/#", $_SERVER["REQUEST_URI"])

answered Mar 09 '20 at 18:23

BerinHardt

145
1
7

score 0 · Accepted Answer · answered Mar 09 '20 at 18:23

You can use parse_url function to parse the URL data and process the URI path accordingly.

<?php

$url = 'http://a.com/php/abcpdf/';

$url_data = parse_url($url);

if(strpos(trim($url_data['path'],'/') . "/","php/") !== false){
    echo "exists"; // your task
}

Demo: https://3v4l.org/XQlF1

php preg_match or php regex to find word

2 Answers2