Python - How to replace a character and a digit while keeping the digit the same?

Question

I want to replace \n in front of any digit in mystring, while keeping the digit the same as before. I tried the following.

mystring = "\n this \n 1. is \n 2. some \n 3. text \n"
k = re.sub('\n \d', '\d', mystring)
k

I do not want to replace all "\n". Only the ones in front digits. However in my output, the digits are replaced with "\d" and I want to know how to keep them the same.

My output:

'\n this \\d. is \\d. some \\d. text \n'

expected output

'\n this 1. is 2. some 3. text \n'

Do you mean `\n (\d)` and replace with `\1`? https://regex101.com/r/IQ40o4/1 — The fourth bird, Mar 11 '20 at 21:06
Can't you just remove all newlines, and then add one to each end of the string? — AMC, Mar 11 '20 at 21:10

score 1 · Accepted Answer · answered Mar 11 '20 at 21:13

You could use a capturing group \n (\d) and in the replacement use r"\1"

To match 1 or more digits use \d+

Regex demo | Python demo

For example

import re
mystring = "\n this \n 1. is \n 2. some \n 3. text \n"
k = re.sub(r"\n (\d)", r"\1", mystring)
print(k)

Output

this 1. is 2. some 3. text

Python - How to replace a character and a digit while keeping the digit the same?

1 Answers1